Archive for the ‘ integers ’ Category

Author: Ian Stewart Posted: Fri Sep 03, 2010 5:46 pm (GMT -7) Yes, when you divide by an integer n, the only possible remainders are 0, 1, 2, 3, …, n-1. And when you divide each number in a set of n consecutive integers by n, you’ll get each of these remainders exactly once

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Problem Solving :: RE: a question about remainders

Problem Solving :: a question about remainders

Author: mepinoargote Subject: a question about remainders Posted: Fri Sep 03, 2010 5:31 pm (GMT -7) When a possitive integer is divided by 7, the only possible remainders are 0,1,2,3,4,5 and 6. Also, each of these remainders will occur exactly once when the terms in a sequence of 7 consecutive integers are divided by 7. This is an explanation i got from OG about remainders, Can i generalize this rule when dividing a possitive integer by any n possitive integer

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Problem Solving :: a question about remainders

Author: beatthegmatinsept Posted: Fri Sep 03, 2010 4:13 pm (GMT -7) diebeatsthegmat wrote: Is the product of all integers in a set S positive? a. The product of the smallest and greatest integers is positive

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Data Sufficiency :: RE: a manhattan DS

Data Sufficiency :: a manhattan DS

Author: diebeatsthegmat Subject: a manhattan DS Posted: Fri Sep 03, 2010 3:54 pm (GMT -7) Is the product of all integers in a set S positive? a

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Data Sufficiency :: a manhattan DS

Author: diebeatsthegmat Subject: a manhattan DS Posted: Fri Sep 03, 2010 3:54 pm (GMT -7) Is the product of all integers in a set S positive?

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Data Sufficiency :: a manhattan DS

Author: Rahul@gurome Posted: Fri Sep 03, 2010 12:17 am (GMT -7) Solution: Let the integers be x, x+1, x+2, x+3……..x+9. So x + (x+1) + (x+2) + (x+3) + (x+4) = 560.

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Problem Solving :: RE: First-degree equations

Author: Rahul@gurome Posted: Fri Sep 03, 2010 12:17 am (GMT -7) Solution: Let the integers be x, x+1, x+2, x+3……..x+9. So x + (x+1) + (x+2) + (x+3) + (x+4) = 560.

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Problem Solving :: RE: First-degree equations

Author: pullagurla Subject: First-degree equations Posted: Thu Sep 02, 2010 11:36 pm (GMT -7) In an increasing sequence of 10 consecutive integers, the sum of the � rst 5 integers is 560.

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Problem Solving :: First-degree equations

Problem Solving :: prime integer

Author: blaster Subject: prime integer Posted: Thu Sep 02, 2010 11:01 pm (GMT -7) If y ≠ 3 and 2x/y is a prime integer greater than 2, which of the following must be true? I. x = y II.

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Problem Solving :: prime integer